(1) Calculate the i) mass and ii) volume at r.t.p of oxygen gas required to convert 6g of carbon to carbon (IV) oxide. (C=12, O=16) molar gas volume at r.t.p = 24dm
Step IV
2 Calculate the mass of the oxygen gas used.
1 mole carbon = 12g
1 mole oxygen gas = 32g
C(s)+O2(g)→CO2(g)
12g of carbon needed 32g of oxygen gas
:. 6g of carbon requires Ng of oxygen gas
Step V
Solve for the value of N
   
N=x 32
    
=g